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12x^2+115x-50=0
a = 12; b = 115; c = -50;
Δ = b2-4ac
Δ = 1152-4·12·(-50)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15625}=125$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(115)-125}{2*12}=\frac{-240}{24} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(115)+125}{2*12}=\frac{10}{24} =5/12 $
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